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[1][2][3] A \land ( ), \lor ( ), \lnot ( ) : 0 ( ) 1 ( ) , a, b c A :

 a \lor (b \lor c) = (a \lor b) \lor c  a \land (b \land c) = (a \land b) \land c
 a \lor b = b \lor a  a \land b = b \land a
 a \lor (a \land b) = a  a \land (a \lor b) = a
 a \lor (b \land c) = (a \lor b) \land (a \lor c)  a \land (b \lor c) = (a \land b) \lor (a \land c)
 a \lor \lnot a = 1  a \land \lnot a = 0

, (A, \land, \lor) . , , . , , , .

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, 0, 1, ¬a a . a b A :

 a \lor a = a;  a \land a = a ;
 a \lor 0 = a ;  a \land 1 = a ;
 a \lor 1 = 1 ;  a \land 0 = 0 ;
 \lnot 0 = 1 ;  \lnot 1 = 0 ; 0 1
 \lnot (a \lor b) = \lnot a \land \lnot b;  \lnot (a \land b) = \lnot a \lor \lnot b;
 \lnot \lnot a = a .

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, .

, :

 a \lor b = b \lor a ;  a \land b = b \land a . 1
 a \lor (b \lor c) = (a \lor b) \lor c ;  a \land (b \land c) = (a \land b) \land c . 2
3.1  a \lor (b \land c) = (a \lor b) \land (a \lor c) 3.2  a \land (b \lor c) = (a \land b) \lor (a \land c) 3
 a \lor \lnot a = 1 ;  a \land \lnot a = 0 . 4 ( )
 \lnot (a \lor b) = \lnot a \land \lnot b;  \lnot (a \land b) = \lnot a \lor \lnot b. 5
 a \lor (a \land b) = a ;  a \land (a \lor b) = a . 6
a \lor(\lnot a \land b) = a \lor b; a \land(\lnot a \lor b) = a \land b. 7 -
 a \lor a = a;  a \land a = a . 8
 \lnot \lnot a = a . 9
 a \lor 0 = a ;  a \land 1 = a . 10
 a \lor 1 = 1 ;  a \land 0 = 0 .
0 1  \lnot 0 = 1 ; 1 0  \lnot 1 = 0 .
 (a \lor b)\land(\lnot a \lor b)=b;   (a \land b) \lor (\lnot a \land b)=b. 11

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1933 . :

  1. : x + y = y + x.
  2. : (x + y) + z = x + (y + z).
  3. : n(n(x) + y) + n(n(x) + n(y)) = x.

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  1. : x + y = y + x.
  2. : (x + y) + z = x + (y + z).
  3. : n(n(x + y') + n(x + n(y))) = x.

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  1. D. A. Vladimirov Springer Online Reference Works - Boolean algebra  (.). Springer-Verlag (2002). 9 2012. 4 2010.
  2. . . .: «», 1969.  . 19.
  3. . ., - . ..: , 1988.  . 58.

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